Indefinite Integration formulas
Master Indefinite Integration through 34 JEE Advanced-level formulas, systematically structured with every variable spelled out. Revise concept-wise, identify the areas where you need improvement, and focus your preparation with greater precision.
Indefinite Integration, every formula
34 formulas, typeset and free. Print it, or keep it open beside your practice.
Power rule
Q1MCQPower rule$\displaystyle\int x^{3}\,dx$ equals:- A$\dfrac{x^{4}}{4}+C$
- B$3x^{2}+C$
- C$\dfrac{x^{4}}{3}+C$
- D$x^{4}+C$
- A
Reciprocal
Q1MCQReciprocal$\displaystyle\int\dfrac{1}{x}\,dx$ equals:- A$\ln|x|+C$
- B$-\dfrac{1}{x^{2}}+C$
- C$x^{-1}+C$
- D$\ln x^{2}+C$
- A
Exponential
Q1MCQExponential$\displaystyle\int e^{x}\,dx$ equals:- A$e^{x}+C$
- B$xe^{x-1}+C$
- C$\dfrac{e^{x}}{x}+C$
- D$e^{x}\ln x+C$
- A
General exponential
a>0, a≠1
Q1MCQGeneral exponential$\displaystyle\int 2^{x}\,dx$ equals:- A$\dfrac{2^{x}}{\ln 2}+C$
- B$2^{x}\ln 2+C$
- C$x\,2^{x-1}+C$
- D$\dfrac{2^{x+1}}{x+1}+C$
- A
Sine
Q1MCQSine$\displaystyle\int\sin x\,dx$ equals:- A$-\cos x+C$
- B$\cos x+C$
- C$-\sin x+C$
- D$\sin x+C$
- A
Cosine
Q1MCQCosine$\displaystyle\int\cos x\,dx$ equals:- A$\sin x+C$
- B$-\sin x+C$
- C$\cos x+C$
- D$-\cos x+C$
- A
sec^2
Q1MCQsec^2$\displaystyle\int\sec^{2}x\,dx$ equals:- A$\tan x+C$
- B$-\cot x+C$
- C$\sec x+C$
- D$\tan^{2}x+C$
- A
cosec^2
Q1MCQcosec^2$\displaystyle\int\csc^{2}x\,dx$ equals:- A$-\cot x+C$
- B$\cot x+C$
- C$\tan x+C$
- D$-\csc x+C$
- A
sec·tan
Q1MCQsec·tan$\displaystyle\int\sec x\tan x\,dx$ equals:- A$\sec x+C$
- B$\tan x+C$
- C$\sec^{2}x+C$
- D$-\sec x+C$
- A
Integral of tan
Q1MCQIntegral of tan$\displaystyle\int\tan x\,dx$ equals:- A$\ln|\sec x|+C$
- B$\sec^{2}x+C$
- C$\ln|\cos x|+C$
- D$-\ln|\sec x|+C$
- A
Integral of sec
Q1MCQIntegral of sec$\displaystyle\int\sec x\,dx$ equals:- A$\ln|\sec x+\tan x|+C$
- B$\sec x\tan x+C$
- C$\tan x+C$
- D$\ln|\sec x|+C$
- A
arcsin form
Q1MCQarcsin form$\displaystyle\int\dfrac{dx}{\sqrt{1-x^{2}}}$ equals:- A$\sin^{-1}x+C$
- B$\tan^{-1}x+C$
- C$\cos^{-1}x+C$
- D$\sec^{-1}x+C$
- A
arctan form
Q1MCQarctan form$\displaystyle\int\dfrac{dx}{1+x^{2}}$ equals:- A$\tan^{-1}x+C$
- B$\sin^{-1}x+C$
- C$\ln(1+x^{2})+C$
- D$\cot^{-1}x+C$
- A
Linear substitution
F'=f
Q1MCQLinear substitution$\displaystyle\int\cos(3x)\,dx$ equals:- A$\dfrac{\sin 3x}{3}+C$
- B$\sin 3x+C$
- C$3\sin 3x+C$
- D$-\dfrac{\sin 3x}{3}+C$
- A
Log-derivative rule
Q1MCQLog-derivative$\displaystyle\int\dfrac{2x}{x^{2}+1}\,dx$ equals:- A$\ln(x^{2}+1)+C$
- B$\tan^{-1}x+C$
- C$\dfrac{1}{x^{2}+1}+C$
- D$2\ln x+C$
- A
Power of a function
Q1MCQPower of a function$\displaystyle\int (x^{2}+1)^{3}\,(2x)\,dx$ equals:- A$\dfrac{(x^{2}+1)^{4}}{4}+C$
- B$(x^{2}+1)^{4}+C$
- C$\dfrac{(x^{2}+1)^{3}}{3}+C$
- D$3(x^{2}+1)^{2}+C$
- A
Root of a function
Q1MCQRoot of a function$\displaystyle\int\dfrac{2x}{\sqrt{x^{2}+1}}\,dx$ equals:- A$2\sqrt{x^{2}+1}+C$
- B$\sqrt{x^{2}+1}+C$
- C$\ln\sqrt{x^{2}+1}+C$
- D$\dfrac{1}{\sqrt{x^{2}+1}}+C$
- A
arcsin (a)
Q1MCQarcsin (a)$\displaystyle\int\dfrac{dx}{\sqrt{9-x^{2}}}$ equals:- A$\sin^{-1}\dfrac{x}{3}+C$
- B$\dfrac13\sin^{-1}\dfrac{x}{3}+C$
- C$\sin^{-1}\dfrac{x}{9}+C$
- D$\tan^{-1}\dfrac{x}{3}+C$
- A
arctan (a)
Q1MCQarctan (a)$\displaystyle\int\dfrac{dx}{4+x^{2}}$ equals:- A$\dfrac12\tan^{-1}\dfrac{x}{2}+C$
- B$\tan^{-1}\dfrac{x}{2}+C$
- C$\dfrac14\tan^{-1}\dfrac{x}{2}+C$
- D$\dfrac12\sin^{-1}\dfrac{x}{2}+C$
- A
1/(x^2-a^2)
Q1MCQ1/(x^2-a^2)$\displaystyle\int\dfrac{dx}{x^{2}-9}$ equals:- A$\dfrac{1}{6}\ln\left|\dfrac{x-3}{x+3}\right|+C$
- B$\dfrac{1}{3}\ln\left|\dfrac{x-3}{x+3}\right|+C$
- C$\dfrac{1}{6}\ln\left|\dfrac{x+3}{x-3}\right|+C$
- D$\tan^{-1}\dfrac{x}{3}+C$
- A
1/(a^2-x^2)
Q1MCQ1/sqrt(x^2+a^2)$\displaystyle\int\dfrac{dx}{\sqrt{x^{2}+4}}$ equals:- A$\ln\left|x+\sqrt{x^{2}+4}\right|+C$
- B$\sin^{-1}\dfrac{x}{2}+C$
- C$\dfrac12\ln\left|x+\sqrt{x^{2}+4}\right|+C$
- D$\tan^{-1}\dfrac{x}{2}+C$
- A
1/sqrt(x^2+a^2)
Q1MCQ1/sqrt(x^2-a^2)$\displaystyle\int\dfrac{dx}{\sqrt{x^{2}-1}}$ equals:- A$\ln\left|x+\sqrt{x^{2}-1}\right|+C$
- B$\sin^{-1}x+C$
- C$\sec^{-1}x+C$
- D$\ln|x-1|+C$
- A
1/sqrt(x^2-a^2)
Q1MCQ1/(a^2-x^2)$\displaystyle\int\dfrac{dx}{1-x^{2}}$ equals:- A$\dfrac12\ln\left|\dfrac{1+x}{1-x}\right|+C$
- B$\tan^{-1}x+C$
- C$\sin^{-1}x+C$
- D$\dfrac12\ln\left|\dfrac{1-x}{1+x}\right|+C$
- A
sqrt(a^2-x^2)
Q1MCQsqrt(a^2-x^2)$\displaystyle\int\sqrt{a^{2}-x^{2}}\,dx$ equals:- A$\dfrac{x}{2}\sqrt{a^{2}-x^{2}}+\dfrac{a^{2}}{2}\sin^{-1}\dfrac{x}{a}+C$
- B$\dfrac{(a^{2}-x^{2})^{3/2}}{3}+C$
- C$\dfrac{x}{2}\sqrt{a^{2}-x^{2}}+C$
- D$a^{2}\sin^{-1}\dfrac{x}{a}+C$
- A
sqrt(x^2+a^2)
Q1MCQsqrt(x^2+a^2)The formula for $\displaystyle\int\sqrt{x^{2}+a^{2}}\,dx$ has leading term:- A$\dfrac{x}{2}\sqrt{x^{2}+a^{2}}$
- B$x\sqrt{x^{2}+a^{2}}$
- C$\dfrac{(x^{2}+a^{2})^{3/2}}{3}$
- D$\dfrac{a^{2}}{2}\ln x$
- A
Integration by parts
first fn by ILATE
Q1MCQBy parts (ILATE)In $\displaystyle\int x\,e^{x}\,dx$, by ILATE the first function is:- A$x$
- B$e^{x}$
- C$xe^{x}$
- Deither
- A
e^x [f+f']
Q1MCQe^x[f+f']$\displaystyle\int e^{x}\big(\sin x+\cos x\big)\,dx$ equals:- A$e^{x}\sin x+C$
- B$e^{x}\cos x+C$
- C$e^{x}(\sin x-\cos x)+C$
- D$-e^{x}\cos x+C$
- A
e^x·(sin/cos)
Q1MCQe^x sin$\displaystyle\int e^{x}\sin x\,dx$ equals:- A$\dfrac{e^{x}}{2}(\sin x-\cos x)+C$
- B$\dfrac{e^{x}}{2}(\sin x+\cos x)+C$
- C$e^{x}\sin x+C$
- D$-e^{x}\cos x+C$
- A
x^n·ln x
n≠-1
Q1MCQx^n ln x$\displaystyle\int x\ln x\,dx$ equals:- A$\dfrac{x^{2}}{2}\left(\ln x-\dfrac12\right)+C$
- B$\dfrac{x^{2}}{2}\ln x+C$
- C$x^{2}\ln x+C$
- D$\dfrac{x^{2}}{2}\left(\ln x+\dfrac12\right)+C$
- A
Integral of arcsin
Q1MCQIntegral of arcsin$\displaystyle\int\sin^{-1}x\,dx$ equals:- A$x\sin^{-1}x+\sqrt{1-x^{2}}+C$
- B$x\sin^{-1}x-\sqrt{1-x^{2}}+C$
- C$\sin^{-1}x+C$
- D$\dfrac{(\sin^{-1}x)^{2}}{2}+C$
- A
Integral of arctan
Q1MCQIntegral of arctan$\displaystyle\int\tan^{-1}x\,dx$ equals:- A$x\tan^{-1}x-\dfrac12\ln(1+x^{2})+C$
- B$x\tan^{-1}x+\dfrac12\ln(1+x^{2})+C$
- C$\tan^{-1}x+C$
- D$\dfrac{(\tan^{-1}x)^{2}}{2}+C$
- A
Reduction: sin^n
I_n=∫sin^n x dx
Q1MCQReduction sin^nThe reduction formula for $I_n=\int\sin^{n}x\,dx$ is:- A$\dfrac{-\sin^{n-1}x\cos x}{n}+\dfrac{n-1}{n}I_{n-2}$
- B$\dfrac{\sin^{n-1}x\cos x}{n}+I_{n-2}$
- C$\dfrac{\cos^{n-1}x\sin x}{n}+\dfrac{n-1}{n}I_{n-2}$
- D$\dfrac{\sin^{n+1}x}{n+1}$
- A
Reduction: tan^n
I_n=∫tan^n x dx
Q1MCQReduction tan^nThe reduction formula for $I_n=\int\tan^{n}x\,dx$ is:- A$\dfrac{\tan^{n-1}x}{n-1}-I_{n-2}$
- B$\dfrac{\tan^{n-1}x}{n-1}+I_{n-2}$
- C$\dfrac{\tan^{n+1}x}{n+1}$
- D$\dfrac{\sec^{n-1}x}{n-1}-I_{n-2}$
- A
Weierstrass substitution
for ∫dx/(a+b sin x) etc.
Q1MCQWeierstrass substitutionFor $\displaystyle\int\dfrac{dx}{a+b\sin x}$, the substitution $t=\tan\tfrac{x}{2}$ gives $\sin x=$:- A$\dfrac{2t}{1+t^{2}}$
- B$\dfrac{1-t^{2}}{1+t^{2}}$
- C$\dfrac{2t}{1-t^{2}}$
- D$\dfrac{1+t^{2}}{2t}$
- A
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