Method OF Differentiation formulas
Master Method OF Differentiation through 34 JEE Advanced-level formulas, systematically structured with every variable spelled out. Revise concept-wise, identify the areas where you need improvement, and focus your preparation with greater precision.
Method OF Differentiation, every formula
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Derivative (definition)
Q1MCQDefinition$f'(x)$ is defined as:- A$\lim_{h\to0}\dfrac{f(x+h)-f(x)}{h}$
- B$\lim_{h\to0}f(x+h)$
- C$f(x)$
- D$\lim_{x\to0}f(x)$
- A
Constant
Q1NumericalConstantThe derivative of $f(x)=7$ is:Power rule
Q1MCQPower rule$\dfrac{d}{dx}(x^{5})$ equals:- A$5x^{4}$
- B$x^{4}$
- C$5x^{5}$
- D$4x^{5}$
- A
Exponential
Q1MCQExponential$\dfrac{d}{dx}(e^{x})$ equals:- A$e^{x}$
- B$xe^{x-1}$
- C$e^{x}\ln x$
- D$\dfrac{e^{x}}{x}$
- A
General exponential
Q1MCQGeneral exponential$\dfrac{d}{dx}(2^{x})$ equals:- A$2^{x}\ln 2$
- B$x2^{x-1}$
- C$2^{x}$
- D$\dfrac{2^{x}}{\ln 2}$
- A
Logarithm
Q1MCQLogarithm$\dfrac{d}{dx}(\ln x)$ equals:- A$\dfrac1x$
- B$\ln x$
- C$x$
- D$-\dfrac{1}{x^{2}}$
- A
Sum/difference rule
Q1MCQSum rule$\dfrac{d}{dx}(3x^{2}+2x)$ equals:- A$6x+2$
- B$3x+2$
- C$6x$
- D$5x$
- A
Product rule
Q1MCQProduct rule$\dfrac{d}{dx}(x^{2}e^{x})$ equals:- A$e^{x}(x^{2}+2x)$
- B$2xe^{x}$
- C$x^{2}e^{x}$
- D$e^{x}(x^{2}-2x)$
- A
Quotient rule
Q1MCQQuotient rule$\dfrac{d}{dx}\dfrac{x}{x+1}$ equals:- A$\dfrac{1}{(x+1)^{2}}$
- B$\dfrac{-1}{(x+1)^{2}}$
- C$\dfrac{x}{(x+1)^{2}}$
- D$1$
- A
Chain rule
Q1MCQChain rule$\dfrac{d}{dx}\sin(x^{2})$ equals:- A$2x\cos(x^{2})$
- B$\cos(x^{2})$
- C$2x\sin(x^{2})$
- D$\cos(2x)$
- A
d/dx sin x
Q1MCQsin x$\dfrac{d}{dx}(\sin x)$ equals:- A$\cos x$
- B$-\cos x$
- C$-\sin x$
- D$\sec^{2}x$
- A
d/dx cos x
Q1MCQcos x$\dfrac{d}{dx}(\cos x)$ equals:- A$-\sin x$
- B$\sin x$
- C$-\cos x$
- D$\sec^{2}x$
- A
d/dx tan x
Q1MCQtan x$\dfrac{d}{dx}(\tan x)$ equals:- A$\sec^{2}x$
- B$-\csc^{2}x$
- C$\sec x\tan x$
- D$\cos x$
- A
d/dx cot x
Q1MCQcot x$\dfrac{d}{dx}(\cot x)$ equals:- A$-\csc^{2}x$
- B$\sec^{2}x$
- C$\csc^{2}x$
- D$-\sec x\tan x$
- A
d/dx sec x
Q1MCQsec x$\dfrac{d}{dx}(\sec x)$ equals:- A$\sec x\tan x$
- B$-\csc x\cot x$
- C$\sec^{2}x$
- D$\tan x$
- A
d/dx cosec x
Q1MCQcosec x$\dfrac{d}{dx}(\csc x)$ equals:- A$-\csc x\cot x$
- B$\sec x\tan x$
- C$-\csc^{2}x$
- D$\cot x$
- A
d/dx arcsin
Q1MCQarcsin$\dfrac{d}{dx}(\sin^{-1}x)$ equals:- A$\dfrac{1}{\sqrt{1-x^{2}}}$
- B$\dfrac{-1}{\sqrt{1-x^{2}}}$
- C$\dfrac{1}{1+x^{2}}$
- D$\dfrac{1}{|x|\sqrt{x^{2}-1}}$
- A
d/dx arccos
Q1MCQarccos$\dfrac{d}{dx}(\cos^{-1}x)$ equals:- A$\dfrac{-1}{\sqrt{1-x^{2}}}$
- B$\dfrac{1}{\sqrt{1-x^{2}}}$
- C$\dfrac{-1}{1+x^{2}}$
- D$\dfrac{1}{1+x^{2}}$
- A
d/dx arctan
Q1MCQarctan$\dfrac{d}{dx}(\tan^{-1}x)$ equals:- A$\dfrac{1}{1+x^{2}}$
- B$\dfrac{-1}{1+x^{2}}$
- C$\dfrac{1}{\sqrt{1-x^{2}}}$
- D$\dfrac{1}{1-x^{2}}$
- A
d/dx arccot
Q1MCQarccot$\dfrac{d}{dx}(\cot^{-1}x)$ equals:- A$\dfrac{-1}{1+x^{2}}$
- B$\dfrac{1}{1+x^{2}}$
- C$\dfrac{-1}{\sqrt{1-x^{2}}}$
- D$\dfrac{1}{1-x^{2}}$
- A
d/dx arcsec
Q1MCQarcsec$\dfrac{d}{dx}(\sec^{-1}x)$ equals:- A$\dfrac{1}{|x|\sqrt{x^{2}-1}}$
- B$\dfrac{1}{\sqrt{1-x^{2}}}$
- C$\dfrac{1}{1+x^{2}}$
- D$\dfrac{-1}{|x|\sqrt{x^{2}-1}}$
- A
Log-derivative rule
Q1MCQLog-derivative$\dfrac{d}{dx}\ln(x^{2}+1)$ equals:- A$\dfrac{2x}{x^{2}+1}$
- B$\dfrac{1}{x^{2}+1}$
- C$2x$
- D$\dfrac{2x}{x^{2}}$
- A
Root of a function
Q1MCQRoot of function$\dfrac{d}{dx}\sqrt{x^{2}+1}$ equals:- A$\dfrac{x}{\sqrt{x^{2}+1}}$
- B$\dfrac{2x}{\sqrt{x^{2}+1}}$
- C$\dfrac{1}{2\sqrt{x^{2}+1}}$
- D$\sqrt{x^{2}+1}$
- A
Power of a function
Q1MCQPower of function$\dfrac{d}{dx}(x^{2}+1)^{3}$ equals:- A$6x(x^{2}+1)^{2}$
- B$3(x^{2}+1)^{2}$
- C$(x^{2}+1)^{2}$
- D$6x(x^{2}+1)^{3}$
- A
Parametric derivative
x=f(t), y=g(t)
Q1MCQParametricFor $x=t^{2},\ y=t^{3}$, $\dfrac{dy}{dx}$ equals:- A$\dfrac{3t}{2}$
- B$\dfrac{2}{3t}$
- C$3t^{2}$
- D$\dfrac{2t}{3}$
- A
Implicit differentiation
f(x,y)=0
Q1MCQImplicitFor $x^{2}+y^{2}=25$, $\dfrac{dy}{dx}$ equals:- A$-\dfrac{x}{y}$
- B$\dfrac{x}{y}$
- C$-\dfrac{y}{x}$
- D$\dfrac{y}{x}$
- A
Logarithmic differentiation
Q1MCQLog differentiationFor $y=x^{x}$, we first take:- A$\ln y=x\ln x$
- B$\ln y=x$
- C$y=e^{x}$
- D$\ln y=\ln x$
- A
Derivative of f(x)^{g(x)}
Q1MCQf^g derivativeFor $y=f(x)^{g(x)}$, $y'$ equals:- A$y\left[g'\ln f+g\dfrac{f'}{f}\right]$
- B$gf^{g-1}f'$
- C$f^{g}\ln f$
- D$g'f^{g}$
- A
Higher-order derivative
Q1NumericalHigher orderIf $y=x^{3}$, then $\dfrac{d^{2}y}{dx^{2}}$ at $x=2$ is:d/dx (ax+b)/(cx+d)
Q1MCQ(ax+b)/(cx+d)$\dfrac{d}{dx}\dfrac{2x+1}{x+1}$ equals:- A$\dfrac{1}{(x+1)^{2}}$
- B$\dfrac{2}{(x+1)^{2}}$
- C$\dfrac{3}{(x+1)^{2}}$
- D$\dfrac{-1}{(x+1)^{2}}$
- A
Derivative of even is odd
Q1NumericalEven ⇒ f'(0)If $f$ is an even differentiable function, then $f'(0)$ is:√(a²−x²) substitution
Q1MCQ√(a²−x²) subTo differentiate a function with $\sqrt{a^{2}-x^{2}}$, substitute:- A$x=a\sin\theta$
- B$x=a\tan\theta$
- C$x=a\sec\theta$
- D$x=a\cos 2\theta$
- A
√(a²+x²) substitution
Q1MCQ√(a²+x²) subTo differentiate a function with $\sqrt{a^{2}+x^{2}}$, substitute:- A$x=a\tan\theta$
- B$x=a\sin\theta$
- C$x=a\sec\theta$
- D$x=a\cos\theta$
- A
Infinite nested radical
Q1MCQNested radicalFor $y=\sqrt{f(x)+\sqrt{f(x)+\cdots}}$ (to $\infty$), $\dfrac{dy}{dx}$ equals:- A$\dfrac{f'(x)}{2y-1}$
- B$\dfrac{f'(x)}{2y}$
- C$\dfrac{f'(x)}{y}$
- D$2yf'(x)$
- A
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