Properties AND Solution OF Triangles formulas

Every formula JEE Advanced expects you to know for Properties AND Solution OF Triangles, with the variables spelled out. Free, no sign-up. Read it before a mock, not during one.

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Formulas: 20
Subject: Mathematics
Exam: JEE Advanced
No sign-in needed: ₹0

Properties AND Solution OF Triangles, every formula

20 formulas, typeset and free. Print it, or keep it open beside your practice.

Sine rule
$\frac{a}{sin A} = \frac{b}{sin B} = \frac{c}{sin C} = 2 R$
Cosine rule
$cos A = \frac{b ^{2} + c ^{2} - a ^{2}}{2 b c}$
Projection formula
$a = b cos C + c cos B$
Area (two sides + angle)
$Δ = \frac{1}{2} ab sin C$
Area (Heron)
$Δ = s (s - a) (s - b) (s - c)$
Semi-perimeter
$s = \frac{a + b + c}{2}$
Circumradius
$R = \frac{ab c}{4Δ}$
Inradius
$r = \frac{Δ}{s}$
Tangent half-angle
$tan \frac{A}{2} = \frac{( s - b ) ( s - c )}{s ( s - a )}$
Sine half-angle
$sin \frac{A}{2} = \frac{( s - b ) ( s - c )}{b c}$
Cosine half-angle
$cos \frac{A}{2} = \frac{s ( s - a )}{b c}$
Napier's analogy
$tan \frac{B - C}{2} = \frac{b - c}{b + c} cot \frac{A}{2}$
Area (R form)
$Δ = \frac{ab c}{4 R}$
m-n theorem
$(m + n) cot θ = m cot α - n cot β$
Escribed radius r₁
$r_{1} = \frac{Δ}{s - a}$
Sum of angles
$A + B + C = π$
Area (2R form)
$Δ = 2 R^{2} sin A sin B sin C$
a in terms of R
$a = 2 R sin A$
Distance of incentre from vertex
$A I = \frac{r}{sin ( A /2 )}$
Length of median
$m_{a} = \frac{1}{2} 2 b^{2} + 2 c^{2} - a^{2}$

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Properties AND Solution OF Triangles formulas

Properties AND Solution OF Triangles, every formula

Sine rule

Cosine rule

Projection formula

Area (two sides + angle)

Area (Heron)

Semi-perimeter

Circumradius

Inradius

Tangent half-angle

Sine half-angle

Cosine half-angle

Napier's analogy

Area (R form)

m-n theorem

Escribed radius r₁

Sum of angles

Area (2R form)

a in terms of R

Distance of incentre from vertex

Length of median

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Know the Properties AND Solution OF Triangles formulas. Now use them.

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