Ionic Equilibrium (11th) formulas
Master Ionic Equilibrium (11th) through 22 JEE Advanced-level formulas, systematically structured with every variable spelled out. Revise concept-wise, identify the areas where you need improvement, and focus your preparation with greater precision.
Ionic Equilibrium (11th), every formula
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Ionic product of water
Q1MCQKwThe ionic product of water at $25^{\circ}$C is:- A$10^{-14}$
- B$10^{-7}$
- C$10^{14}$
- D$1$
- A
pH
Q1NumericalpHThe pH of a solution with $[H^{+}]=10^{-3}$ M is:pOH
Q1NumericalpOHThe pOH of a solution with $[OH^{-}]=10^{-4}$ M is:pH + pOH
Q1NumericalpH+pOHIf the pOH of a solution is $5$, its pH is:Acid dissociation constant
Q1MCQKaThe acid dissociation constant is:- A$\dfrac{[H^{+}][A^{-}]}{[HA]}$
- B$\dfrac{[HA]}{[H^{+}][A^{-}]}$
- C$[H^{+}][A^{-}]$
- D$\dfrac{[H^{+}]}{[HA]}$
- A
Base dissociation constant
Q1MCQKbThe base dissociation constant is:- A$\dfrac{[BH^{+}][OH^{-}]}{[B]}$
- B$\dfrac{[B]}{[BH^{+}][OH^{-}]}$
- C$[BH^{+}][OH^{-}]$
- D$\dfrac{[OH^{-}]}{[B]}$
- A
Ka × Kb
Q1MCQKa × KbFor a conjugate acid–base pair, $K_a\times K_b$ equals:- A$K_w$
- B$1$
- C$K_a$
- D$K_w^{2}$
- A
Ostwald's dilution law
Q1MCQOstwaldOstwald's dilution law for a weak acid is:- A$K_a\approx\alpha^{2}C$
- B$K_a=\alpha C$
- C$K_a=\dfrac{\alpha}{C}$
- D$K_a=\alpha^{2}$
- A
Degree of dissociation
Q1MCQDegree of dissociationThe degree of dissociation of a weak acid is:- A$\sqrt{\dfrac{K_a}{C}}$
- B$\dfrac{K_a}{C}$
- C$K_a C$
- D$\sqrt{K_a C}$
- A
[H⁺] of a weak acid
Q1MCQ[H⁺] weak acidThe $[H^{+}]$ of a weak acid of concentration $C$ is:- A$\sqrt{K_a C}$
- B$K_a C$
- C$\dfrac{K_a}{C}$
- D$K_a$
- A
pKa
Q1NumericalpKaFor $K_a=10^{-5}$, the p$K_a$ is:Henderson equation (acid buffer)
Q1MCQHenderson (acid)The Henderson equation for an acidic buffer is:- A$\text{pH}=\text{p}K_a+\log\dfrac{[\text{salt}]}{[\text{acid}]}$
- B$\text{pH}=\text{p}K_a-\log\dfrac{[\text{salt}]}{[\text{acid}]}$
- C$\text{pH}=\text{p}K_a$
- D$\text{pH}=\log[\text{salt}]$
- A
Henderson (base buffer)
Q1MCQHenderson (base)The Henderson equation for a basic buffer gives:- A$\text{pOH}=\text{p}K_b+\log\dfrac{[\text{salt}]}{[\text{base}]}$
- B$\text{pH}=\text{p}K_b$
- C$\text{pOH}=\text{p}K_a$
- D$\text{pOH}=\log[\text{base}]$
- A
Solubility product
Q1MCQKspThe solubility product of $A_xB_y$ is:- A$[A^{+}]^{x}[B^{-}]^{y}$
- B$[A^{+}][B^{-}]$
- C$[A^{+}]^{y}[B^{-}]^{x}$
- D$[A^{+}]+[B^{-}]$
- A
Ksp of a salt AB
S = molar solubility
Q1MCQKsp of ABFor a salt AB of solubility $S$, $K_{sp}$ is:- A$S^{2}$
- B$S$
- C$4S^{3}$
- D$2S$
- A
Ksp of AB₂
Q1MCQKsp of AB₂For a salt $AB_2$ of solubility $S$, $K_{sp}$ is:- A$4S^{3}$
- B$S^{3}$
- C$S^{2}$
- D$2S^{2}$
- A
Common-ion effect
Q1MCQCommon-ion effectAdding a common ion to a weak electrolyte:- Asuppresses its dissociation
- Bincreases dissociation
- Chas no effect
- Dchanges $K_a$
- A
Hydrolysis (salt of weak acid)
Q1MCQSalt hydrolysisThe pH of a salt of a weak acid and strong base is:- A$>7$ (basic)
- B$<7$ (acidic)
- C$=7$
- D$0$
- A
Degree of hydrolysis
Q1MCQDegree of hydrolysisThe degree of hydrolysis of a salt of a weak acid is:- A$\sqrt{\dfrac{K_w}{K_a C}}$
- B$\sqrt{\dfrac{K_a}{C}}$
- C$\dfrac{K_w}{K_a}$
- D$K_a C$
- A
Buffer at half-neutralization
Q1MCQHalf-neutralizationAt half-neutralization of a weak acid, the pH equals:- A$\text{p}K_a$
- B$7$
- C$14$
- D$0$
- A
Neutral solution
Q1NumericalNeutral pHThe pH of pure water at $25^{\circ}$C is:Precipitation condition
Q1MCQPrecipitationA precipitate forms when the ionic product is:- Agreater than $K_{sp}$
- Bless than $K_{sp}$
- Cequal to $K_{sp}$
- Dzero
- A
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