Thermodynamics & Thermochemistry formulas
Master Thermodynamics & Thermochemistry through 22 JEE Advanced-level formulas, systematically structured with every variable spelled out. Revise concept-wise, identify the areas where you need improvement, and focus your preparation with greater precision.
Thermodynamics & Thermochemistry, every formula
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First law of thermodynamics
Q1MCQFirst lawThe first law of thermodynamics is:- A$\Delta U=q+W$
- B$\Delta U=q-W$
- C$q=\Delta U$
- D$W=\Delta U$
- A
Work of expansion
Q1NumericalExpansion workA gas expands by $2$ L against a constant $3$ atm. The work done by the gas (in L·atm, enter magnitude) is:Enthalpy
Q1MCQEnthalpyEnthalpy is defined as:- A$U+PV$
- B$U-PV$
- C$PV$
- D$U$
- A
Enthalpy change
Q1MCQΔH–ΔUFor a gaseous reaction, $\Delta H$ equals:- A$\Delta U+\Delta n_g RT$
- B$\Delta U-\Delta n_g RT$
- C$\Delta U$
- D$\Delta n_g RT$
- A
Heat at constant volume
Q1MCQq at const VAt constant volume, the heat absorbed equals:- A$\Delta U$
- B$\Delta H$
- C$W$
- D$0$
- A
Heat at constant pressure
Q1MCQq at const PAt constant pressure, the heat absorbed equals:- A$\Delta H$
- B$\Delta U$
- C$W$
- D$0$
- A
Isothermal reversible work
Q1MCQIsothermal workThe reversible isothermal work of an ideal gas is:- A$-nRT\ln\dfrac{V_2}{V_1}$
- B$-P\Delta V$
- C$nRT$
- D$0$
- A
Adiabatic condition
Q1MCQAdiabaticIn an adiabatic process:- A$q=0$ and $\Delta U=W$
- B$\Delta U=0$
- C$W=0$
- D$\Delta H=0$
- A
Cp − Cv (ideal gas)
Q1MCQCp − CvFor an ideal gas, $C_p-C_v$ equals:- A$R$
- B$\dfrac{R}{2}$
- C$2R$
- D$0$
- A
Enthalpy of reaction (Hess)
Q1MCQHess's lawBy Hess's law, the enthalpy of reaction is:- A$\sum\Delta H_{prod}-\sum\Delta H_{react}$
- B$\sum\Delta H_{react}-\sum\Delta H_{prod}$
- C$0$
- D$\sum\Delta H_{prod}$
- A
Bond enthalpy
Q1MCQBond enthalpyUsing bond enthalpies, $\Delta H$ equals:- Abonds broken $-$ bonds formed
- Bbonds formed $-$ bonds broken
- Cbonds broken
- D$0$
- A
Entropy change
Q1MCQEntropy changeThe entropy change of a reversible process is:- A$\dfrac{q_{rev}}{T}$
- B$q_{rev}T$
- C$\dfrac{T}{q_{rev}}$
- D$q_{rev}$
- A
Gibbs free energy
Q1MCQGibbs energyThe Gibbs free energy change is:- A$\Delta H-T\Delta S$
- B$\Delta H+T\Delta S$
- C$T\Delta S-\Delta H$
- D$\Delta H$
- A
Spontaneity criterion
Q1MCQSpontaneityA process is spontaneous when:- A$\Delta G<0$
- B$\Delta G>0$
- C$\Delta G=0$
- D$\Delta H<0$ only
- A
Free energy and equilibrium
Q1MCQΔG° and KThe relation between $\Delta G^{\circ}$ and the equilibrium constant is:- A$\Delta G^{\circ}=-RT\ln K$
- B$\Delta G^{\circ}=RT\ln K$
- C$\Delta G^{\circ}=-\dfrac{RT}{\ln K}$
- D$\Delta G^{\circ}=K$
- A
Entropy of surroundings
Q1MCQEntropy of surroundingsThe entropy change of the surroundings is:- A$-\dfrac{\Delta H}{T}$
- B$\dfrac{\Delta H}{T}$
- C$\Delta H T$
- D$0$
- A
Second law
Q1MCQSecond lawFor a spontaneous process, the total entropy change is:- A$>0$
- B$<0$
- C$=0$
- Dundefined
- A
Heat capacity
Q1NumericalHeat capacityHeating $2$ mol of a gas ($C=20$ J/mol·K) by $5$ K requires (in J):Enthalpy of neutralization
strong acid + strong base
Q1MCQNeutralizationThe enthalpy of neutralization of a strong acid and strong base is about:- A$-57.1$ kJ/mol
- B$-13.6$ kJ/mol
- C$-100$ kJ/mol
- D$0$
- A
Relation ΔG and ΔG°
Q1MCQΔG and QThe relation between $\Delta G$ and $\Delta G^{\circ}$ is:- A$\Delta G=\Delta G^{\circ}+RT\ln Q$
- B$\Delta G=\Delta G^{\circ}-RT\ln Q$
- C$\Delta G=RT\ln Q$
- D$\Delta G=\Delta G^{\circ}$
- A
Efficiency of a Carnot engine
Q1NumericalCarnotA Carnot engine works between $600$ K and $300$ K. Its efficiency (%) is:Internal energy (ideal gas)
Q1MCQΔU ideal gasThe internal energy change of an ideal gas is:- A$nC_v\Delta T$
- B$nC_p\Delta T$
- C$nR\Delta T$
- D$0$
- A
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