Kinematics 1-D formulas
Master Kinematics 1-D through 30 JEE Advanced-level formulas, systematically structured with every variable spelled out. Revise concept-wise, identify the areas where you need improvement, and focus your preparation with greater precision.
Kinematics 1-D, every formula
30 formulas, typeset and free. Print it, or keep it open beside your practice.
Displacement
change in position
Q1NumericalDisplacementA particle moves from $x=2$ m to $x=9$ m. Its displacement is:Average velocity
Q1NumericalAverage velocityA body covers a displacement of $20$ m in $4$ s. Its average velocity is:Average speed
Q1NumericalAverage speedA car travels $60$ km in $2$ h. Its average speed is (km/h):Instantaneous velocity
Q1MCQInstantaneous velocityInstantaneous velocity is defined as:- A$\dfrac{dx}{dt}$
- B$\dfrac{\Delta x}{\Delta t}$
- C$\dfrac{dv}{dt}$
- D$x\cdot t$
- A
Average acceleration
Q1NumericalAverage accelerationVelocity changes from $2$ to $10$ m/s in $4$ s. The average acceleration is:Instantaneous acceleration
Q1MCQInstantaneous accelerationInstantaneous acceleration is:- A$\dfrac{dv}{dt}$
- B$\dfrac{dx}{dt}$
- C$\dfrac{\Delta x}{\Delta t}$
- D$vt$
- A
First equation of motion
Q1Numericalv=u+atA body starts at $2$ m/s with acceleration $3\ \text{m/s}^2$. Its velocity after $4$ s is:Second equation of motion
Q1Numericals=ut+½at²From rest with $a=2\ \text{m/s}^2$, the distance in $3$ s is:Third equation of motion
Q1Numericalv²=u²+2asA body starting from rest with $a=2\ \text{m/s}^2$ has velocity after $9$ m of:Average-velocity equation
Q1NumericalAverage-velocity eqnA body accelerates uniformly from $2$ to $8$ m/s over $4$ s. Distance covered is:Distance in nth second
Q1Numericalnth secondFrom rest with $a=2\ \text{m/s}^2$, the distance in the $3$rd second is:Acceleration as v·dv/dx
Q1MCQa = v dv/dxWhen acceleration is a function of position, $a$ equals:- A$v\dfrac{dv}{dx}$
- B$\dfrac{dv}{dt}$
- C$\dfrac{dx}{dt}$
- D$\dfrac{d^{2}v}{dx^{2}}$
- A
Free fall from rest (speed)
u=0
Q1NumericalFree fall speedA stone dropped from rest reaches speed after $2$ s (take $g=10$):Free fall from rest (distance)
Q1NumericalFree fall distanceA body dropped from rest falls in $3$ s (take $g=10$) a distance of:Maximum height (vertical throw)
Q1NumericalMax heightA ball is thrown up at $20$ m/s ($g=10$). Its maximum height is:Time of flight (vertical throw)
Q1NumericalTime of flightA ball thrown up at $20$ m/s ($g=10$) has time of flight:Time to fall from height h
Q1NumericalTime to fallThe time for a body to fall $5$ m from rest ($g=10$) is:Speed on reaching ground
Q1NumericalGround speedA body dropped from $20$ m ($g=10$) hits the ground at speed:Galileo's odd-number ratio
equal time intervals
Q1MCQGalileo ratioFor a freely falling body, distances in successive equal time intervals are in the ratio:- A$1:3:5:\cdots$
- B$1:2:3:\cdots$
- C$1:4:9:\cdots$
- D$1:1:1:\cdots$
- A
Slope of x–t graph
Q1MCQx–t slopeThe slope of a position–time graph gives:- Avelocity
- Bacceleration
- Cdisplacement
- Ddistance
- A
Slope of v–t graph
Q1MCQv–t slopeThe slope of a velocity–time graph gives:- Aacceleration
- Bvelocity
- Cdisplacement
- Djerk
- A
Area under v–t graph
Q1MCQv–t areaThe area under a velocity–time graph gives:- Adisplacement
- Bacceleration
- Cvelocity
- Dspeed
- A
Area under a–t graph
Q1MCQa–t areaThe area under an acceleration–time graph gives:- Achange in velocity
- Bdisplacement
- Cvelocity
- Ddistance
- A
Slope of v²–x graph
Q1MCQv²–x slopeThe slope of a $v^{2}$ versus $x$ graph equals:- A$2a$
- B$a$
- C$v$
- D$\dfrac{a}{2}$
- A
Relative velocity (1-D)
Q1NumericalRelative velocityCar A moves at $30$ m/s, car B at $20$ m/s in the same direction. Velocity of A relative to B is:Three-object throw relation
up, down, dropped from same height
Q1MCQThree-object throwFor three bodies from the same height (thrown up $t_1$, down $t_2$, dropped $t_3$), $t_3$ equals:- A$\sqrt{t_1 t_2}$
- B$t_1+t_2$
- C$\dfrac{t_1+t_2}{2}$
- D$t_1-t_2$
- A
Distance vs displacement
Q1MCQDistance vs displacementFor any motion, distance is:- A$\ge|\text{displacement}|$
- B$\le|\text{displacement}|$
- C$=$ displacement always
- D$=0$
- A
a = f(t) integration
Q1MCQa=f(t)When $a=f(t)$, velocity is found from:- A$\int dv=\int a\,dt$
- B$\int v\,dv=\int a\,dx$
- C$v=at$
- D$a=v\dfrac{dv}{dx}$
- A
a = f(x) integration
Q1MCQa=f(x)When $a=f(x)$, one uses:- A$\int v\,dv=\int a\,dx$
- B$\int dv=\int a\,dt$
- C$v=u+at$
- D$s=ut$
- A
Speed–velocity relation
Q1MCQSpeed vs velocityThe magnitude of average velocity compared with average speed is:- A$\le$
- B$\ge$
- C$=$ always
- Dunrelated
- A
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