Vectors formulas
Master Vectors through 30 JEE Advanced-level formulas, systematically structured with every variable spelled out. Revise concept-wise, identify the areas where you need improvement, and focus your preparation with greater precision.
Vectors, every formula
30 formulas, typeset and free. Print it, or keep it open beside your practice.
Magnitude of a vector
Q1NumericalMagnitudeThe magnitude of $\vec A=3\hat i+4\hat j$ is:Unit vector
Q1MCQUnit vectorThe unit vector along $\vec A=6\hat i+8\hat j$ is:- A$0.6\hat i+0.8\hat j$
- B$6\hat i+8\hat j$
- C$\hat i+\hat j$
- D$\dfrac{1}{14}(6\hat i+8\hat j)$
- A
Components of a vector
Q1MCQComponentsThe horizontal component of a vector $A$ at angle $\theta$ is:- A$A\cos\theta$
- B$A\sin\theta$
- C$A\tan\theta$
- D$A$
- A
Parallelogram law (resultant)
Q1NumericalResultantTwo perpendicular vectors of magnitudes $3$ and $4$ have resultant:Direction of resultant
Q1MCQResultant directionThe direction of the resultant of $\vec A,\vec B$ (angle $\theta$) satisfies:- A$\tan\alpha=\dfrac{B\sin\theta}{A+B\cos\theta}$
- B$\tan\alpha=\dfrac{B}{A}$
- C$\tan\alpha=\dfrac{A\sin\theta}{B}$
- D$\alpha=\theta$
- A
Maximum resultant
Q1NumericalMax resultantTwo vectors of magnitudes $3$ and $5$ have maximum resultant:Minimum resultant
Q1NumericalMin resultantTwo vectors of magnitudes $3$ and $5$ have minimum resultant:Perpendicular vectors' resultant
Q1MCQPerpendicular resultantFor two perpendicular vectors, the resultant magnitude is:- A$\sqrt{A^{2}+B^{2}}$
- B$A+B$
- C$|A-B|$
- D$AB$
- A
Position & displacement vector
Q1MCQDisplacement vectorThe vector from point $A$ to point $B$ is:- A$\vec b-\vec a$
- B$\vec a-\vec b$
- C$\vec a+\vec b$
- D$\dfrac{\vec a+\vec b}{2}$
- A
Distance between two points
Q1NumericalDistanceThe distance between points with position vectors $(1,0,0)$ and $(4,0,0)$ is:Section formula
Q1MCQSection formulaThe point dividing $\vec a,\vec b$ internally in ratio $m:n$ is:- A$\dfrac{n\vec a+m\vec b}{m+n}$
- B$\dfrac{m\vec a+n\vec b}{m+n}$
- C$\dfrac{\vec a+\vec b}{2}$
- D$m\vec b-n\vec a$
- A
Midpoint
Q1MCQMidpointThe midpoint of $\vec a$ and $\vec b$ is:- A$\dfrac{\vec a+\vec b}{2}$
- B$\vec a+\vec b$
- C$\dfrac{\vec b-\vec a}{2}$
- D$\dfrac{\vec a+\vec b}{3}$
- A
Dot product (definition)
Q1NumericalDot definitionIf $A=2,\ B=3,\ \theta=60^{\circ}$, then $\vec A\cdot\vec B$ is:Dot product (components)
Q1NumericalDot componentsIf $\vec A=(1,2,2),\ \vec B=(2,1,2)$, then $\vec A\cdot\vec B$ is:Angle via dot product
Q1MCQAngleThe angle between two vectors satisfies:- A$\cos\theta=\dfrac{\vec A\cdot\vec B}{AB}$
- B$\sin\theta=\dfrac{\vec A\cdot\vec B}{AB}$
- C$\cos\theta=\vec A\cdot\vec B$
- D$\cos\theta=AB$
- A
Perpendicular condition
Q1MCQPerpendicularTwo nonzero vectors are perpendicular iff:- A$\vec A\cdot\vec B=0$
- B$\vec A\times\vec B=0$
- C$\vec A=\vec B$
- D$A=B$
- A
Projection
Q1NumericalProjectionThe projection of $\vec A=(3,4,0)$ on $\vec B=(1,0,0)$ is:Unit-vector dot products
Q1NumericalDot i·iThe value of $\hat i\cdot\hat i$ is:Cross product (definition)
Q1MCQCross definition$|\vec A\times\vec B|$ equals:- A$AB\sin\theta$
- B$AB\cos\theta$
- C$AB$
- D$A+B$
- A
Cross product (determinant)
Q1MCQCross determinant$\hat i\times\hat j$ equals:- A$\hat k$
- B$-\hat k$
- C$\hat i$
- D$0$
- A
Magnitude of cross product
Q1MCQArea$|\vec A\times\vec B|$ represents:- Athe area of the parallelogram of sides $\vec A,\vec B$
- Bthe dot product
- Cthe projection
- Dthe resultant
- A
Parallel condition
Q1MCQParallelTwo nonzero vectors are parallel iff:- A$\vec A\times\vec B=0$
- B$\vec A\cdot\vec B=0$
- C$A=B$
- D$\vec A=-\vec B$
- A
Anticommutativity
Q1MCQAnticommutativity$\vec A\times\vec B$ equals:- A$-(\vec B\times\vec A)$
- B$\vec B\times\vec A$
- C$\vec A\cdot\vec B$
- D$0$
- A
Unit-vector cross products
Q1MCQCross j×k$\hat j\times\hat k$ equals:- A$\hat i$
- B$\hat k$
- C$-\hat i$
- D$\hat j$
- A
Scalar triple product
Q1MCQScalar triple product$[\vec A\ \vec B\ \vec C]$ equals:- A$\vec A\cdot(\vec B\times\vec C)$
- B$\vec A\times(\vec B\cdot\vec C)$
- C$\vec A\cdot\vec B\cdot\vec C$
- D$(\vec A\times\vec B)\times\vec C$
- A
Coplanarity
Q1MCQCoplanarityThree vectors are coplanar iff their scalar triple product is:- A$0$
- B$1$
- Cpositive
- D$\infty$
- A
Vector triple product
Q1MCQVector triple product$\vec A\times(\vec B\times\vec C)$ equals:- A$(\vec A\cdot\vec C)\vec B-(\vec A\cdot\vec B)\vec C$
- B$(\vec A\cdot\vec B)\vec C-(\vec A\cdot\vec C)\vec B$
- C$\vec A\cdot\vec B\cdot\vec C$
- D$0$
- A
Lami's theorem
three concurrent forces
Q1MCQLami's theoremFor three concurrent forces in equilibrium, Lami's theorem states:- A$\dfrac{A}{\sin\alpha}=\dfrac{B}{\sin\beta}=\dfrac{C}{\sin\gamma}$
- B$A+B+C=0$
- C$A=B=C$
- D$\dfrac{A}{\cos\alpha}=\dfrac{B}{\cos\beta}$
- A
|A+B|²
Q1MCQ|A+B|²$|\vec A+\vec B|^{2}$ equals:- A$A^{2}+B^{2}+2AB\cos\theta$
- B$A^{2}+B^{2}$
- C$A^{2}+B^{2}-2AB\cos\theta$
- D$(A+B)^{2}$
- A
Work (dot product)
Q1NumericalWorkA force $\vec F=(2,0,0)$ N causes displacement $\vec d=(3,0,0)$ m. The work is:
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