Work Energy AND Power formulas
Master Work Energy AND Power through 28 JEE Advanced-level formulas, systematically structured with every variable spelled out. Revise concept-wise, identify the areas where you need improvement, and focus your preparation with greater precision.
Work Energy AND Power, every formula
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Work by a constant force
Q1NumericalWork constant forceA force of $10$ N moves a body $5$ m along the force. The work done is:Work by a variable force
Q1MCQVariable forceThe work done by a variable force is:- A$\int\vec F\cdot d\vec s$
- B$FS$
- C$\dfrac{F}{s}$
- D$F+s$
- A
Kinetic energy
Q1NumericalKinetic energyA $2$ kg body moves at $3$ m/s. Its kinetic energy is:KE–momentum relation
Q1MCQKE–momentumKinetic energy in terms of momentum is:- A$\dfrac{p^{2}}{2m}$
- B$\dfrac{p}{2m}$
- C$2mp$
- D$\dfrac{p^{2}}{m}$
- A
Momentum from KE
Q1MCQMomentum from KEThe momentum of a body with kinetic energy $K$ is:- A$\sqrt{2mK}$
- B$2mK$
- C$\dfrac{K}{m}$
- D$\sqrt{mK}$
- A
Work–energy theorem
Q1NumericalWork–energy theoremA net work of $12$ J is done on a body initially at rest ($K_i=0$). Its final KE is:Potential energy
Q1MCQPotential energyThe potential energy is related to work by a conservative force as:- A$U=-W$
- B$U=W$
- C$U=2W$
- D$U=W^{2}$
- A
Conservative force from PE
Q1MCQForce from PEA conservative force equals:- A$-\dfrac{dU}{dx}$
- B$\dfrac{dU}{dx}$
- C$U x$
- D$-U$
- A
Gravitational PE
Q1NumericalGravitational PEA $2$ kg body is raised $5$ m ($g=10$). Its gain in PE is:Elastic (spring) PE
Q1NumericalSpring PEA spring of $k=200$ N/m is stretched $0.1$ m. Its elastic PE is:Conservation of mechanical energy
conservative forces only
Q1MCQEnergy conservationWhen only conservative forces act, the quantity conserved is:- A$K+U$
- B$K$ only
- C$U$ only
- D$K-U$
- A
Change in PE
Q1MCQChange in PEThe change in potential energy equals:- A$-W_c$
- B$W_c$
- C$\Delta K$
- D$0$
- A
Average power
Q1NumericalAverage powerA machine does $600$ J of work in $3$ s. Its average power is:Instantaneous power
Q1NumericalInstantaneous powerA force of $10$ N acts on a body moving at $4$ m/s along the force. The power is:Work by gravity
rising
Q1MCQWork by gravityThe work done by gravity on a body rising a height $h$ is:- A$-mgh$
- B$+mgh$
- C$0$
- D$\tfrac12 mgh$
- A
Work by a spring
Q1MCQWork by a springThe work done by a spring stretched by $x$ is:- A$-\tfrac12 kx^{2}$
- B$\tfrac12 kx^{2}$
- C$kx$
- D$-kx$
- A
Work by friction
Q1NumericalWork by frictionA friction force of $5$ N acts over $4$ m. The work done by friction is:Stable equilibrium
Q1MCQStable equilibriumAt a point of stable equilibrium:- A$\dfrac{dU}{dx}=0,\ \dfrac{d^{2}U}{dx^{2}}>0$
- B$\dfrac{d^{2}U}{dx^{2}}<0$
- C$\dfrac{dU}{dx}\neq0$
- D$U=0$
- A
Unstable equilibrium
Q1MCQUnstable equilibriumAt a point of unstable equilibrium:- A$\dfrac{d^{2}U}{dx^{2}}<0$
- B$\dfrac{d^{2}U}{dx^{2}}>0$
- C$\dfrac{d^{2}U}{dx^{2}}=0$
- D$U=0$
- A
Neutral equilibrium
Q1MCQNeutral equilibriumAt a point of neutral equilibrium:- A$\dfrac{d^{2}U}{dx^{2}}=0$
- B$\dfrac{d^{2}U}{dx^{2}}>0$
- C$\dfrac{d^{2}U}{dx^{2}}<0$
- D$\dfrac{dU}{dx}\neq0$
- A
Conservative force (curl)
Q1MCQConservative force curlA force field is conservative iff:- A$\nabla\times\vec F=0$
- B$\nabla\cdot\vec F=0$
- C$\vec F=0$
- D$\nabla\times\vec F\neq0$
- A
Horsepower
Q1NumericalHorsepowerHow many watts is $2$ horsepower (take $1\ \text{HP}=746$ W)?Work as area
Q1MCQWork as areaThe work done by a force from an $F$–$x$ graph is:- Athe area under the curve
- Bthe slope
- Cthe peak value
- Dthe x-intercept
- A
KE is non-negative
Q1MCQKE signKinetic energy is always:- A$\ge0$
- B$\le0$
- Cnegative
- Dzero
- A
Modified work–energy theorem
Q1MCQModified WE theoremFor non-conservative and pseudo work, $W_{NC}+W_{PS}$ equals:- A$\Delta E$ (change in total mechanical energy)
- B$\Delta K$
- C$\Delta U$
- D$0$
- A
Power–velocity (constant P)
Q1NumericalPower–velocityAn engine of constant power $100$ W pulls at $5$ m/s. The pulling force is:Efficiency
Q1NumericalEfficiencyA machine gives $80$ J output for $100$ J input. Its efficiency (%) is:Work done in a round trip (conservative)
Q1NumericalRound tripThe work done by a conservative force over a closed loop is:
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